6v^2+18v=240

Solution for 6v^2+18v=240 equation:

6v^2+18v=240

We move all terms to the left:

6v^2+18v-(240)=0

a = 6; b = 18; c = -240;
Δ = b2-4ac
Δ = 182-4·6·(-240)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-78}{2*6}=\frac{-96}{12}
=-8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+78}{2*6}=\frac{60}{12}
=5
$